Base | Representation |
---|---|
bin | 100000111111011100… |
… | …000001101101100001 |
3 | 10101102202121012012111 |
4 | 200333130001231201 |
5 | 1040022024100032 |
6 | 24135032155321 |
7 | 2362561312516 |
oct | 407734015541 |
9 | 111382535174 |
10 | 35424050017 |
11 | 14028a530a4 |
12 | 6a47538b41 |
13 | 3457035c55 |
14 | 1a0097130d |
15 | dc4de4c47 |
hex | 83f701b61 |
35424050017 has 2 divisors, whose sum is σ = 35424050018. Its totient is φ = 35424050016.
The previous prime is 35424049967. The next prime is 35424050027. The reversal of 35424050017 is 71005042453.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 33176436736 + 2247613281 = 182144^2 + 47409^2 .
It is an emirp because it is prime and its reverse (71005042453) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 35424050017 - 211 = 35424047969 is a prime.
It is a super-3 number, since 3×354240500173 (a number of 33 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (35424050027) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17712025008 + 17712025009.
It is an arithmetic number, because the mean of its divisors is an integer number (17712025009).
Almost surely, 235424050017 is an apocalyptic number.
It is an amenable number.
35424050017 is a deficient number, since it is larger than the sum of its proper divisors (1).
35424050017 is an equidigital number, since it uses as much as digits as its factorization.
35424050017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 16800, while the sum is 31.
The spelling of 35424050017 in words is "thirty-five billion, four hundred twenty-four million, fifty thousand, seventeen".
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