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35424050027 is a prime number
BaseRepresentation
bin100000111111011100…
…000001101101101011
310101102202121012012212
4200333130001231223
51040022024100102
624135032155335
72362561312532
oct407734015553
9111382535185
1035424050027
1114028a53103
126a47538b4b
133457035c62
141a00971319
15dc4de4c52
hex83f701b6b

35424050027 has 2 divisors, whose sum is σ = 35424050028. Its totient is φ = 35424050026.

The previous prime is 35424050017. The next prime is 35424050029. The reversal of 35424050027 is 72005042453.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 35424050027 - 26 = 35424049963 is a prime.

It is a super-3 number, since 3×354240500273 (a number of 33 digits) contains 333 as substring.

Together with 35424050029, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 35424049975 and 35424050002.

It is not a weakly prime, because it can be changed into another prime (35424050029) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17712025013 + 17712025014.

It is an arithmetic number, because the mean of its divisors is an integer number (17712025014).

Almost surely, 235424050027 is an apocalyptic number.

35424050027 is a deficient number, since it is larger than the sum of its proper divisors (1).

35424050027 is an equidigital number, since it uses as much as digits as its factorization.

35424050027 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 33600, while the sum is 32.

The spelling of 35424050027 in words is "thirty-five billion, four hundred twenty-four million, fifty thousand, twenty-seven".