Base | Representation |
---|---|
bin | 100000111111011100… |
… | …000001101110101001 |
3 | 10101102202121012022011 |
4 | 200333130001232221 |
5 | 1040022024100324 |
6 | 24135032155521 |
7 | 2362561312651 |
oct | 407734015651 |
9 | 111382535264 |
10 | 35424050089 |
11 | 14028a5315a |
12 | 6a47538ba1 |
13 | 3457035cac |
14 | 1a00971361 |
15 | dc4de4c94 |
hex | 83f701ba9 |
35424050089 has 2 divisors, whose sum is σ = 35424050090. Its totient is φ = 35424050088.
The previous prime is 35424050087. The next prime is 35424050131. The reversal of 35424050089 is 98005042453.
35424050089 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 35012771689 + 411278400 = 187117^2 + 20280^2 .
It is a cyclic number.
It is not a de Polignac number, because 35424050089 - 21 = 35424050087 is a prime.
It is a super-3 number, since 3×354240500893 (a number of 33 digits) contains 333 as substring.
Together with 35424050087, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (35424050087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17712025044 + 17712025045.
It is an arithmetic number, because the mean of its divisors is an integer number (17712025045).
Almost surely, 235424050089 is an apocalyptic number.
It is an amenable number.
35424050089 is a deficient number, since it is larger than the sum of its proper divisors (1).
35424050089 is an equidigital number, since it uses as much as digits as its factorization.
35424050089 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 172800, while the sum is 40.
The spelling of 35424050089 in words is "thirty-five billion, four hundred twenty-four million, fifty thousand, eighty-nine".
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