Base | Representation |
---|---|
bin | 110011100011001010001… |
… | …000010010010100000111 |
3 | 110112122200000202212000212 |
4 | 303203022020102110013 |
5 | 431014411210043303 |
6 | 11311213145430035 |
7 | 513635033031152 |
oct | 63431210222407 |
9 | 13478600685025 |
10 | 3542444221703 |
11 | 1146384459152 |
12 | 49267149b31b |
13 | 1c908823015a |
14 | c3653178c99 |
15 | 6223171cad8 |
hex | 338ca212507 |
3542444221703 has 2 divisors, whose sum is σ = 3542444221704. Its totient is φ = 3542444221702.
The previous prime is 3542444221649. The next prime is 3542444221777. The reversal of 3542444221703 is 3071224442453.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3542444221703 is a prime.
It is a super-3 number, since 3×35424442217033 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3542444221403) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1771222110851 + 1771222110852.
It is an arithmetic number, because the mean of its divisors is an integer number (1771222110852).
Almost surely, 23542444221703 is an apocalyptic number.
3542444221703 is a deficient number, since it is larger than the sum of its proper divisors (1).
3542444221703 is an equidigital number, since it uses as much as digits as its factorization.
3542444221703 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 645120, while the sum is 41.
The spelling of 3542444221703 in words is "three trillion, five hundred forty-two billion, four hundred forty-four million, two hundred twenty-one thousand, seven hundred three".
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