Base | Representation |
---|---|
bin | 100000111111100100… |
… | …110001100111001011 |
3 | 10101102220220201002112 |
4 | 200333210301213023 |
5 | 1040023120441441 |
6 | 24135153252535 |
7 | 2362616643626 |
oct | 407744614713 |
9 | 111386821075 |
10 | 35426343371 |
11 | 1402a27a131 |
12 | 6a4826414b |
13 | 3457659a73 |
14 | 1a00daadbd |
15 | dc51e94eb |
hex | 83f9319cb |
35426343371 has 2 divisors, whose sum is σ = 35426343372. Its totient is φ = 35426343370.
The previous prime is 35426343349. The next prime is 35426343373. The reversal of 35426343371 is 17334362453.
It is a strong prime.
It is an emirp because it is prime and its reverse (17334362453) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 35426343371 - 222 = 35422149067 is a prime.
It is a super-3 number, since 3×354263433713 (a number of 33 digits) contains 333 as substring.
Together with 35426343373, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (35426343373) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17713171685 + 17713171686.
It is an arithmetic number, because the mean of its divisors is an integer number (17713171686).
Almost surely, 235426343371 is an apocalyptic number.
35426343371 is a deficient number, since it is larger than the sum of its proper divisors (1).
35426343371 is an equidigital number, since it uses as much as digits as its factorization.
35426343371 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 544320, while the sum is 41.
The spelling of 35426343371 in words is "thirty-five billion, four hundred twenty-six million, three hundred forty-three thousand, three hundred seventy-one".
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