Base | Representation |
---|---|
bin | 110011100101101010011… |
… | …101000001100001011011 |
3 | 110112220121111002101100111 |
4 | 303211222131001201123 |
5 | 431040413301400012 |
6 | 11312340113145151 |
7 | 514061503623643 |
oct | 63455235014133 |
9 | 13486544071314 |
10 | 3545134012507 |
11 | 114753480185a |
12 | 4930a225b1b7 |
13 | 1c93c6580a49 |
14 | c382a4b1523 |
15 | 6233c937ba7 |
hex | 3396a74185b |
3545134012507 has 2 divisors, whose sum is σ = 3545134012508. Its totient is φ = 3545134012506.
The previous prime is 3545134012477. The next prime is 3545134012531. The reversal of 3545134012507 is 7052104315453.
3545134012507 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is an emirp because it is prime and its reverse (7052104315453) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 3545134012507 - 219 = 3545133488219 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3545134012507.
It is not a weakly prime, because it can be changed into another prime (3545134012547) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1772567006253 + 1772567006254.
It is an arithmetic number, because the mean of its divisors is an integer number (1772567006254).
Almost surely, 23545134012507 is an apocalyptic number.
3545134012507 is a deficient number, since it is larger than the sum of its proper divisors (1).
3545134012507 is an equidigital number, since it uses as much as digits as its factorization.
3545134012507 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 252000, while the sum is 40.
The spelling of 3545134012507 in words is "three trillion, five hundred forty-five billion, one hundred thirty-four million, twelve thousand, five hundred seven".
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