Base | Representation |
---|---|
bin | 110011100101101010011… |
… | …101000001100001110011 |
3 | 110112220121111002101101101 |
4 | 303211222131001201303 |
5 | 431040413301400111 |
6 | 11312340113145231 |
7 | 514061503624006 |
oct | 63455235014163 |
9 | 13486544071341 |
10 | 3545134012531 |
11 | 1147534801881 |
12 | 4930a225b217 |
13 | 1c93c6580a67 |
14 | c382a4b153d |
15 | 6233c937bc1 |
hex | 3396a741873 |
3545134012531 has 2 divisors, whose sum is σ = 3545134012532. Its totient is φ = 3545134012530.
The previous prime is 3545134012507. The next prime is 3545134012547. The reversal of 3545134012531 is 1352104315453.
3545134012531 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3545134012531 - 225 = 3545100458099 is a prime.
It is a super-2 number, since 2×35451340125312 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (3545134012561) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1772567006265 + 1772567006266.
It is an arithmetic number, because the mean of its divisors is an integer number (1772567006266).
Almost surely, 23545134012531 is an apocalyptic number.
3545134012531 is a deficient number, since it is larger than the sum of its proper divisors (1).
3545134012531 is an equidigital number, since it uses as much as digits as its factorization.
3545134012531 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 108000, while the sum is 37.
Adding to 3545134012531 its reverse (1352104315453), we get a palindrome (4897238327984).
The spelling of 3545134012531 in words is "three trillion, five hundred forty-five billion, one hundred thirty-four million, twelve thousand, five hundred thirty-one".
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