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354514313225441 is a prime number
BaseRepresentation
bin101000010011011011100101…
…1101101010010010011100001
31201111020020102000212110021102
41100212313023231102103201
5332431330303141203231
63253553343245004145
7134446546111414145
oct12046671355222341
91644206360773242
10354514313225441
11a2a60748712806
12339172ba253655
13122a773022b945
1463788274d3225
152aebae6962acb
hex1426dcbb524e1

354514313225441 has 2 divisors, whose sum is σ = 354514313225442. Its totient is φ = 354514313225440.

The previous prime is 354514313225411. The next prime is 354514313225483. The reversal of 354514313225441 is 144522313415453.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 333977818003600 + 20536495221841 = 18275060^2 + 4531721^2 .

It is a cyclic number.

It is not a de Polignac number, because 354514313225441 - 214 = 354514313209057 is a prime.

It is not a weakly prime, because it can be changed into another prime (354514313225411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177257156612720 + 177257156612721.

It is an arithmetic number, because the mean of its divisors is an integer number (177257156612721).

Almost surely, 2354514313225441 is an apocalyptic number.

It is an amenable number.

354514313225441 is a deficient number, since it is larger than the sum of its proper divisors (1).

354514313225441 is an equidigital number, since it uses as much as digits as its factorization.

354514313225441 is an evil number, because the sum of its binary digits is even.

The product of its digits is 3456000, while the sum is 47.

The spelling of 354514313225441 in words is "three hundred fifty-four trillion, five hundred fourteen billion, three hundred thirteen million, two hundred twenty-five thousand, four hundred forty-one".