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35452047133 is a prime number
BaseRepresentation
bin100001000001000110…
…110100111100011101
310101111201021121000201
4201001012310330131
51040101211002013
624141512223501
72363351266666
oct410106647435
9111451247021
1035452047133
1114042835808
126a5499ab91
13345ca893a9
141a0457c36d
15dc75c53dd
hex8411b4f1d

35452047133 has 2 divisors, whose sum is σ = 35452047134. Its totient is φ = 35452047132.

The previous prime is 35452047089. The next prime is 35452047139. The reversal of 35452047133 is 33174025453.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 22872630169 + 12579416964 = 151237^2 + 112158^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-35452047133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 35452047092 and 35452047101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (35452047139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17726023566 + 17726023567.

It is an arithmetic number, because the mean of its divisors is an integer number (17726023567).

Almost surely, 235452047133 is an apocalyptic number.

It is an amenable number.

35452047133 is a deficient number, since it is larger than the sum of its proper divisors (1).

35452047133 is an equidigital number, since it uses as much as digits as its factorization.

35452047133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 151200, while the sum is 37.

The spelling of 35452047133 in words is "thirty-five billion, four hundred fifty-two million, forty-seven thousand, one hundred thirty-three".