Base | Representation |
---|---|
bin | 110011100101110111101… |
… | …001100111010111010001 |
3 | 110112221011220200220021102 |
4 | 303211313221213113101 |
5 | 431041341441321131 |
6 | 11312414102434145 |
7 | 514100132550134 |
oct | 63456751472721 |
9 | 13487156626242 |
10 | 3545355417041 |
11 | 1147638784309 |
12 | 493144432955 |
13 | 1c94303c0849 |
14 | c384ba6621b |
15 | 623520be1cb |
hex | 33977a675d1 |
3545355417041 has 2 divisors, whose sum is σ = 3545355417042. Its totient is φ = 3545355417040.
The previous prime is 3545355417017. The next prime is 3545355417047. The reversal of 3545355417041 is 1407145535453.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1911317310016 + 1634038107025 = 1382504^2 + 1278295^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3545355417041 is a prime.
It is not a weakly prime, because it can be changed into another prime (3545355417047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1772677708520 + 1772677708521.
It is an arithmetic number, because the mean of its divisors is an integer number (1772677708521).
Almost surely, 23545355417041 is an apocalyptic number.
It is an amenable number.
3545355417041 is a deficient number, since it is larger than the sum of its proper divisors (1).
3545355417041 is an equidigital number, since it uses as much as digits as its factorization.
3545355417041 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2520000, while the sum is 47.
The spelling of 3545355417041 in words is "three trillion, five hundred forty-five billion, three hundred fifty-five million, four hundred seventeen thousand, forty-one".
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