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354544143124447 is a prime number
BaseRepresentation
bin101000010011101001011110…
…1101101010100011111011111
31201111100002101221002022221201
41100213102331231110133133
5332432322401114440242
63254015155243140331
7134451653244363553
oct12047227555243737
91644302357068851
10354544143124447
11a2a72365935401
12339210442146a7
13122aa4a52a7763
14637a0570dd863
152aec79068b4b7
hex14274bdb547df

354544143124447 has 2 divisors, whose sum is σ = 354544143124448. Its totient is φ = 354544143124446.

The previous prime is 354544143124427. The next prime is 354544143124511. The reversal of 354544143124447 is 744421341445453.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-354544143124447 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (354544143124427) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177272071562223 + 177272071562224.

It is an arithmetic number, because the mean of its divisors is an integer number (177272071562224).

Almost surely, 2354544143124447 is an apocalyptic number.

354544143124447 is a deficient number, since it is larger than the sum of its proper divisors (1).

354544143124447 is an equidigital number, since it uses as much as digits as its factorization.

354544143124447 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 51609600, while the sum is 55.

The spelling of 354544143124447 in words is "three hundred fifty-four trillion, five hundred forty-four billion, one hundred forty-three million, one hundred twenty-four thousand, four hundred forty-seven".