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355005424041997 is a prime number
BaseRepresentation
bin101000010111000000010010…
…0001100011000000000001101
31201112222012001101111212020111
41100232000210030120000031
5333012402102023320442
63255011123530120021
7134530203231445021
oct12056004414300015
91645865041455214
10355005424041997
11a312aa55999103
123399651a280011
1312311b38859351
1463944d5d0a381
152b0978bea8b17
hex142e02431800d

355005424041997 has 2 divisors, whose sum is σ = 355005424041998. Its totient is φ = 355005424041996.

The previous prime is 355005424041953. The next prime is 355005424042001. The reversal of 355005424041997 is 799140424500553.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 347487402948196 + 7518021093801 = 18641014^2 + 2741901^2 .

It is an emirp because it is prime and its reverse (799140424500553) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 355005424041997 - 235 = 354971064303629 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (355005424041937) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177502712020998 + 177502712020999.

It is an arithmetic number, because the mean of its divisors is an integer number (177502712020999).

Almost surely, 2355005424041997 is an apocalyptic number.

It is an amenable number.

355005424041997 is a deficient number, since it is larger than the sum of its proper divisors (1).

355005424041997 is an equidigital number, since it uses as much as digits as its factorization.

355005424041997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27216000, while the sum is 58.

The spelling of 355005424041997 in words is "three hundred fifty-five trillion, five billion, four hundred twenty-four million, forty-one thousand, nine hundred ninety-seven".