35504520133 has 2 divisors, whose sum is σ = 35504520134. Its totient is φ = 35504520132.

The previous prime is 35504520091. The next prime is 35504520143. The reversal of 35504520133 is 33102540553.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 28943196129 + 6561324004 = 170127^2 + 81002^2 .

It is a cyclic number.

It is not a de Polignac number, because 35504520133 - 2²⁹ = 34967649221 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 35504520095 and 35504520104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (35504520143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17752260066 + 17752260067.

It is an arithmetic number, because the mean of its divisors is an integer number (17752260067).

Almost surely, 2^35504520133 is an apocalyptic number.

It is an amenable number.

35504520133 is a deficient number, since it is larger than the sum of its proper divisors (1).

35504520133 is an equidigital number, since it uses as much as digits as its factorization.

35504520133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27000, while the sum is 31.

The spelling of 35504520133 in words is "thirty-five billion, five hundred four million, five hundred twenty thousand, one hundred thirty-three".