Base | Representation |
---|---|
bin | 10000001001100100111011… |
… | …11111000000010001010111 |
3 | 11122202001101201000120111112 |
4 | 20010302131333000101113 |
5 | 14123323011134024143 |
6 | 203310352115525235 |
7 | 10323522103350515 |
oct | 1004623577002127 |
9 | 148661351016445 |
10 | 35513440142423 |
11 | 10352190143a31 |
12 | 3b968ab2b981b |
13 | 16a7b97c7ab79 |
14 | 8aac06d354b5 |
15 | 418bbd022e18 |
hex | 204c9dfc0457 |
35513440142423 has 2 divisors, whose sum is σ = 35513440142424. Its totient is φ = 35513440142422.
The previous prime is 35513440142417. The next prime is 35513440142527. The reversal of 35513440142423 is 32424104431553.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-35513440142423 is a prime.
It is a super-4 number, since 4×355134401424234 (a number of 55 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (35513440142623) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17756720071211 + 17756720071212.
It is an arithmetic number, because the mean of its divisors is an integer number (17756720071212).
Almost surely, 235513440142423 is an apocalyptic number.
35513440142423 is a deficient number, since it is larger than the sum of its proper divisors (1).
35513440142423 is an equidigital number, since it uses as much as digits as its factorization.
35513440142423 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 691200, while the sum is 41.
Adding to 35513440142423 its reverse (32424104431553), we get a palindrome (67937544573976).
The spelling of 35513440142423 in words is "thirty-five trillion, five hundred thirteen billion, four hundred forty million, one hundred forty-two thousand, four hundred twenty-three".
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