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355320123414413 is a prime number
BaseRepresentation
bin101000011001010010110100…
…1101111001101011110001101
31201121002021100022220101011012
41100302211221233031132031
5333033031103043230123
63255411451121535005
7134562013616124503
oct12062455157153615
91647067308811135
10355320123414413
11a3241466544473
1233a275064a4465
131233570bb46651
1463a582b378673
152b12a59d97378
hex1432969bcd78d

355320123414413 has 2 divisors, whose sum is σ = 355320123414414. Its totient is φ = 355320123414412.

The previous prime is 355320123414407. The next prime is 355320123414461. The reversal of 355320123414413 is 314414321023553.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 206186251300969 + 149133872113444 = 14359187^2 + 12212038^2 .

It is a cyclic number.

It is not a de Polignac number, because 355320123414413 - 210 = 355320123413389 is a prime.

It is a super-2 number, since 2×3553201234144132 (a number of 30 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (355320123414013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177660061707206 + 177660061707207.

It is an arithmetic number, because the mean of its divisors is an integer number (177660061707207).

Almost surely, 2355320123414413 is an apocalyptic number.

It is an amenable number.

355320123414413 is a deficient number, since it is larger than the sum of its proper divisors (1).

355320123414413 is an equidigital number, since it uses as much as digits as its factorization.

355320123414413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 518400, while the sum is 41.

Adding to 355320123414413 its reverse (314414321023553), we get a palindrome (669734444437966).

The spelling of 355320123414413 in words is "three hundred fifty-five trillion, three hundred twenty billion, one hundred twenty-three million, four hundred fourteen thousand, four hundred thirteen".