Base | Representation |
---|---|
bin | 101000011010110110100111… |
… | …1011111011101010001100011 |
3 | 1201121211202111211021011122222 |
4 | 1100311231033133131101203 |
5 | 333100034003422121034 |
6 | 3300054132450421255 |
7 | 134613341435242634 |
oct | 12065551737352143 |
9 | 1647752454234588 |
10 | 355534431442019 |
11 | a331433a870575 |
12 | 33a60b5589182b |
13 | 1234c9a352333b |
14 | 63b1d5b7d588b |
15 | 2b183ee4e712e |
hex | 1435b4f7dd463 |
355534431442019 has 2 divisors, whose sum is σ = 355534431442020. Its totient is φ = 355534431442018.
The previous prime is 355534431442013. The next prime is 355534431442037. The reversal of 355534431442019 is 910244134435553.
It is a weak prime.
It is an emirp because it is prime and its reverse (910244134435553) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 355534431442019 - 216 = 355534431376483 is a prime.
It is a super-2 number, since 2×3555344314420192 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (355534431442013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 177767215721009 + 177767215721010.
It is an arithmetic number, because the mean of its divisors is an integer number (177767215721010).
Almost surely, 2355534431442019 is an apocalyptic number.
355534431442019 is a deficient number, since it is larger than the sum of its proper divisors (1).
355534431442019 is an equidigital number, since it uses as much as digits as its factorization.
355534431442019 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552000, while the sum is 53.
The spelling of 355534431442019 in words is "three hundred fifty-five trillion, five hundred thirty-four billion, four hundred thirty-one million, four hundred forty-two thousand, nineteen".
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