35801966147 has 2 divisors, whose sum is σ = 35801966148. Its totient is φ = 35801966146.

The previous prime is 35801966141. The next prime is 35801966149. The reversal of 35801966147 is 74166910853.

35801966147 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 35801966147 - 2¹⁴ = 35801949763 is a prime.

Together with 35801966149, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 35801966095 and 35801966104.

It is not a weakly prime, because it can be changed into another prime (35801966141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 17900983073 + 17900983074.

It is an arithmetic number, because the mean of its divisors is an integer number (17900983074).

Almost surely, 2^35801966147 is an apocalyptic number.

35801966147 is a deficient number, since it is larger than the sum of its proper divisors (1).

35801966147 is an equidigital number, since it uses as much as digits as its factorization.

35801966147 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1088640, while the sum is 50.

The spelling of 35801966147 in words is "thirty-five billion, eight hundred one million, nine hundred sixty-six thousand, one hundred forty-seven".