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36394354152017 is a prime number
BaseRepresentation
bin10000100011001101110001…
…00011010001001001010001
311202212021012010010212221022
420101212320203101021101
514232241114130331032
6205223200244205225
710444256011032251
oct1021467043211121
9152767163125838
1036394354152017
1110661839135734
1240b9577699815
13173cc8551c614
148db6d359b961
15431a79b7b512
hex2119b88d1251

36394354152017 has 2 divisors, whose sum is σ = 36394354152018. Its totient is φ = 36394354152016.

The previous prime is 36394354151951. The next prime is 36394354152053. The reversal of 36394354152017 is 71025145349363.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 36373250488576 + 21103663441 = 6031024^2 + 145271^2 .

It is an emirp because it is prime and its reverse (71025145349363) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 36394354152017 - 244 = 18802168107601 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 36394354152017.

It is not a weakly prime, because it can be changed into another prime (36394354152617) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 18197177076008 + 18197177076009.

It is an arithmetic number, because the mean of its divisors is an integer number (18197177076009).

Almost surely, 236394354152017 is an apocalyptic number.

It is an amenable number.

36394354152017 is a deficient number, since it is larger than the sum of its proper divisors (1).

36394354152017 is an equidigital number, since it uses as much as digits as its factorization.

36394354152017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8164800, while the sum is 53.

The spelling of 36394354152017 in words is "thirty-six trillion, three hundred ninety-four billion, three hundred fifty-four million, one hundred fifty-two thousand, seventeen".