Base | Representation |
---|---|
bin | 100001111001110110… |
… | …010000010010110111 |
3 | 10110222001120000101022 |
4 | 201321312100102313 |
5 | 1044023411112043 |
6 | 24420200051355 |
7 | 2426060633342 |
oct | 417166202267 |
9 | 113861500338 |
10 | 36404004023 |
11 | 14491125042 |
12 | 707b763b5b |
13 | 3582074aaa |
14 | 1a94b81459 |
15 | e30e66868 |
hex | 879d904b7 |
36404004023 has 2 divisors, whose sum is σ = 36404004024. Its totient is φ = 36404004022.
The previous prime is 36404003929. The next prime is 36404004079. The reversal of 36404004023 is 32040040463.
36404004023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 36404004023 - 230 = 35330262199 is a prime.
It is a super-3 number, since 3×364040040233 (a number of 33 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 36404003983 and 36404004001.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (36404004083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 18202002011 + 18202002012.
It is an arithmetic number, because the mean of its divisors is an integer number (18202002012).
Almost surely, 236404004023 is an apocalyptic number.
36404004023 is a deficient number, since it is larger than the sum of its proper divisors (1).
36404004023 is an equidigital number, since it uses as much as digits as its factorization.
36404004023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6912, while the sum is 26.
Adding to 36404004023 its reverse (32040040463), we get a palindrome (68444044486).
The spelling of 36404004023 in words is "thirty-six billion, four hundred four million, four thousand, twenty-three".
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