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3666350053 is a prime number
BaseRepresentation
bin1101101010001000…
…0000111111100101
3100110111212212202201
43122202000333211
530002041200203
61403450334501
7156566314132
oct33242007745
910414785681
103666350053
111611617073
12863a2a431
13465771502
1426ad01589
15166d1ae1d
hexda880fe5

3666350053 has 2 divisors, whose sum is σ = 3666350054. Its totient is φ = 3666350052.

The previous prime is 3666350003. The next prime is 3666350063. The reversal of 3666350053 is 3500536663.

3666350053 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2887772644 + 778577409 = 53738^2 + 27903^2 .

It is a cyclic number.

It is not a de Polignac number, because 3666350053 - 29 = 3666349541 is a prime.

It is a super-2 number, since 2×36663500532 = 26884245422266205618, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 3666349994 and 3666350021.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3666350003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1833175026 + 1833175027.

It is an arithmetic number, because the mean of its divisors is an integer number (1833175027).

Almost surely, 23666350053 is an apocalyptic number.

It is an amenable number.

3666350053 is a deficient number, since it is larger than the sum of its proper divisors (1).

3666350053 is an equidigital number, since it uses as much as digits as its factorization.

3666350053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 145800, while the sum is 37.

The square root of 3666350053 is about 60550.3926742015. The cubic root of 3666350053 is about 1541.9772843468.

The spelling of 3666350053 in words is "three billion, six hundred sixty-six million, three hundred fifty thousand, fifty-three".