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3740054053649 is a prime number
BaseRepresentation
bin110110011011001100100…
…101111110001100010001
3111020112201210112102100112
4312123030211332030101
5442234112314204044
611542053534131105
7534132011631164
oct66331445761421
914215653472315
103740054053649
11121216a012751
12504a20650a95
132118bb2c68b4
14cd03ba39adb
1567449e0e09e
hex366cc97e311

3740054053649 has 2 divisors, whose sum is σ = 3740054053650. Its totient is φ = 3740054053648.

The previous prime is 3740054053613. The next prime is 3740054053651. The reversal of 3740054053649 is 9463504500473.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3726231819025 + 13822234624 = 1930345^2 + 117568^2 .

It is a cyclic number.

It is not a de Polignac number, because 3740054053649 - 216 = 3740053988113 is a prime.

It is a Sophie Germain prime.

Together with 3740054053651, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 3740054053597 and 3740054053606.

It is not a weakly prime, because it can be changed into another prime (3740054053949) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1870027026824 + 1870027026825.

It is an arithmetic number, because the mean of its divisors is an integer number (1870027026825).

Almost surely, 23740054053649 is an apocalyptic number.

It is an amenable number.

3740054053649 is a deficient number, since it is larger than the sum of its proper divisors (1).

3740054053649 is an equidigital number, since it uses as much as digits as its factorization.

3740054053649 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5443200, while the sum is 50.

The spelling of 3740054053649 in words is "three trillion, seven hundred forty billion, fifty-four million, fifty-three thousand, six hundred forty-nine".