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380428374842471 is a prime number
BaseRepresentation
bin101011001111111110110001…
…0001001010001110001100111
31211212222121010112122022211102
41112133331202021101301213
5344330414302424424341
63425034214400230315
7143063020525650614
oct12637754211216147
91755877115568742
10380428374842471
1110024184994009a
123680169900b39b
131343731b366887
1469d2b8dc3550b
152deac35c9bc9b
hex159ff62251c67

380428374842471 has 2 divisors, whose sum is σ = 380428374842472. Its totient is φ = 380428374842470.

The previous prime is 380428374842447. The next prime is 380428374842491. The reversal of 380428374842471 is 174248473824083.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 380428374842471 - 26 = 380428374842407 is a prime.

It is a super-3 number, since 3×3804283748424713 (a number of 45 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 380428374842398 and 380428374842407.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (380428374842491) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 190214187421235 + 190214187421236.

It is an arithmetic number, because the mean of its divisors is an integer number (190214187421236).

Almost surely, 2380428374842471 is an apocalyptic number.

380428374842471 is a deficient number, since it is larger than the sum of its proper divisors (1).

380428374842471 is an equidigital number, since it uses as much as digits as its factorization.

380428374842471 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 231211008, while the sum is 65.

The spelling of 380428374842471 in words is "three hundred eighty trillion, four hundred twenty-eight billion, three hundred seventy-four million, eight hundred forty-two thousand, four hundred seventy-one".