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38100530943413 is a prime number
BaseRepresentation
bin10001010100110111110001…
…00111001101010110110101
311222220101010111210020000222
420222123320213031112311
514443214341410142123
6213011050422144125
711011446450336101
oct1052337047152665
9158811114706028
1038100530943413
111115a387490aa4
12433417a882045
131834b31840433
1495a10b3b8901
154611378a56c8
hex22a6f89cd5b5

38100530943413 has 2 divisors, whose sum is σ = 38100530943414. Its totient is φ = 38100530943412.

The previous prime is 38100530943341. The next prime is 38100530943451. The reversal of 38100530943413 is 31434903500183.

Together with previous prime (38100530943341) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 36672011170564 + 1428519772849 = 6055742^2 + 1195207^2 .

It is a cyclic number.

It is not a de Polignac number, because 38100530943413 - 220 = 38100529894837 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (38100530948413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19050265471706 + 19050265471707.

It is an arithmetic number, because the mean of its divisors is an integer number (19050265471707).

Almost surely, 238100530943413 is an apocalyptic number.

It is an amenable number.

38100530943413 is a deficient number, since it is larger than the sum of its proper divisors (1).

38100530943413 is an equidigital number, since it uses as much as digits as its factorization.

38100530943413 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 466560, while the sum is 44.

The spelling of 38100530943413 in words is "thirty-eight trillion, one hundred billion, five hundred thirty million, nine hundred forty-three thousand, four hundred thirteen".