Base | Representation |
---|---|
bin | 110111100011111001110… |
… | …001011101001000010001 |
3 | 111112000020110010001112121 |
4 | 313203321301131020101 |
5 | 1000024003042400001 |
6 | 12042004253254241 |
7 | 542564415561625 |
oct | 67437161351021 |
9 | 14460213101477 |
10 | 3818121450001 |
11 | 1242290025031 |
12 | 517b89194381 |
13 | 21907cc20a51 |
14 | d2b25c61185 |
15 | 694b88ce6a1 |
hex | 378f9c5d211 |
3818121450001 has 2 divisors, whose sum is σ = 3818121450002. Its totient is φ = 3818121450000.
The previous prime is 3818121449951. The next prime is 3818121450007. The reversal of 3818121450001 is 1000541218183.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3575215398976 + 242906051025 = 1890824^2 + 492855^2 .
It is a cyclic number.
It is not a de Polignac number, because 3818121450001 - 29 = 3818121449489 is a prime.
It is not a weakly prime, because it can be changed into another prime (3818121450007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1909060725000 + 1909060725001.
It is an arithmetic number, because the mean of its divisors is an integer number (1909060725001).
Almost surely, 23818121450001 is an apocalyptic number.
It is an amenable number.
3818121450001 is a deficient number, since it is larger than the sum of its proper divisors (1).
3818121450001 is an equidigital number, since it uses as much as digits as its factorization.
3818121450001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7680, while the sum is 34.
Adding to 3818121450001 its reverse (1000541218183), we get a palindrome (4818662668184).
The spelling of 3818121450001 in words is "three trillion, eight hundred eighteen billion, one hundred twenty-one million, four hundred fifty thousand, one".
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