Search a number
-
+
38400417792013 is a prime number
BaseRepresentation
bin10001011101100110010110…
…10000110000000000001101
312000222001012010210120020111
420232303023100300000031
520013123023423321023
6213400524114120021
711042224102443124
oct1056631320600015
9160861163716214
1038400417792013
1111265586823a42
124382312280011
1318571b40a2444
1496a8394a4abb
15468d3a16300d
hex22eccb43000d

38400417792013 has 2 divisors, whose sum is σ = 38400417792014. Its totient is φ = 38400417792012.

The previous prime is 38400417791969. The next prime is 38400417792019. The reversal of 38400417792013 is 31029771400483.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 38189408938564 + 211008853449 = 6179758^2 + 459357^2 .

It is an emirp because it is prime and its reverse (31029771400483) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 38400417792013 - 237 = 38262978838541 is a prime.

It is a super-2 number, since 2×384004177920132 (a number of 28 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (38400417792019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19200208896006 + 19200208896007.

It is an arithmetic number, because the mean of its divisors is an integer number (19200208896007).

Almost surely, 238400417792013 is an apocalyptic number.

It is an amenable number.

38400417792013 is a deficient number, since it is larger than the sum of its proper divisors (1).

38400417792013 is an equidigital number, since it uses as much as digits as its factorization.

38400417792013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1016064, while the sum is 49.

The spelling of 38400417792013 in words is "thirty-eight trillion, four hundred billion, four hundred seventeen million, seven hundred ninety-two thousand, thirteen".