38430012497 has 2 divisors, whose sum is σ = 38430012498. Its totient is φ = 38430012496.

The previous prime is 38430012493. The next prime is 38430012499. The reversal of 38430012497 is 79421003483.

38430012497 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 35624297536 + 2805714961 = 188744^2 + 52969^2 .

It is a cyclic number.

It is not a de Polignac number, because 38430012497 - 2² = 38430012493 is a prime.

Together with 38430012499, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (38430012493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19215006248 + 19215006249.

It is an arithmetic number, because the mean of its divisors is an integer number (19215006249).

Almost surely, 2^38430012497 is an apocalyptic number.

It is an amenable number.

38430012497 is a deficient number, since it is larger than the sum of its proper divisors (1).

38430012497 is an equidigital number, since it uses as much as digits as its factorization.

38430012497 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 145152, while the sum is 41.

The spelling of 38430012497 in words is "thirty-eight billion, four hundred thirty million, twelve thousand, four hundred ninety-seven".