Base | Representation |
---|---|
bin | 10001100011111010001110… |
… | …11111010001110011001111 |
3 | 12001201202212120111021201212 |
4 | 20301331013133101303033 |
5 | 20030201112041340142 |
6 | 214044304144125035 |
7 | 11064001314624161 |
oct | 1061750737216317 |
9 | 161652776437655 |
10 | 38617250340047 |
11 | 11339536081665 |
12 | 43b834700677b |
13 | 187178b7b53c2 |
14 | 977128d16931 |
15 | 46e7cb233d82 |
hex | 231f477d1ccf |
38617250340047 has 2 divisors, whose sum is σ = 38617250340048. Its totient is φ = 38617250340046.
The previous prime is 38617250340041. The next prime is 38617250340101. The reversal of 38617250340047 is 74004305271683.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-38617250340047 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 38617250339977 and 38617250340004.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (38617250340041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19308625170023 + 19308625170024.
It is an arithmetic number, because the mean of its divisors is an integer number (19308625170024).
Almost surely, 238617250340047 is an apocalyptic number.
38617250340047 is a deficient number, since it is larger than the sum of its proper divisors (1).
38617250340047 is an equidigital number, since it uses as much as digits as its factorization.
38617250340047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3386880, while the sum is 50.
The spelling of 38617250340047 in words is "thirty-eight trillion, six hundred seventeen billion, two hundred fifty million, three hundred forty thousand, forty-seven".
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