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39094502441 is a prime number
BaseRepresentation
bin100100011010001101…
…101100010000101001
310201220120012111100212
4210122031230100221
51120031143034231
625543150510505
72552540534141
oct443215542051
9121816174325
1039094502441
1115641911355
1276b0805435
1338c05b27a7
141c6c21d921
15103c27142b
hex91a36c429

39094502441 has 2 divisors, whose sum is σ = 39094502442. Its totient is φ = 39094502440.

The previous prime is 39094502431. The next prime is 39094502443. The reversal of 39094502441 is 14420549093.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 33496320400 + 5598182041 = 183020^2 + 74821^2 .

It is a cyclic number.

It is not a de Polignac number, because 39094502441 - 210 = 39094501417 is a prime.

It is a super-2 number, since 2×390945024412 (a number of 22 digits) contains 22 as substring.

Together with 39094502443, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (39094502443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19547251220 + 19547251221.

It is an arithmetic number, because the mean of its divisors is an integer number (19547251221).

Almost surely, 239094502441 is an apocalyptic number.

It is an amenable number.

39094502441 is a deficient number, since it is larger than the sum of its proper divisors (1).

39094502441 is an equidigital number, since it uses as much as digits as its factorization.

39094502441 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 155520, while the sum is 41.

The spelling of 39094502441 in words is "thirty-nine billion, ninety-four million, five hundred two thousand, four hundred forty-one".