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3912494611661 = 7395115290651
BaseRepresentation
bin111000111011110010110…
…110011111110011001101
3111212000211110212101200022
4320323302312133303031
51003100242110033121
612153213013511525
7552445156323626
oct70736266376315
914760743771608
103912494611661
111279309234209
125323266425a5
13224c3ca6a13c
14d751988ca4d
156bb8db42aab
hex38ef2d9fccd

3912494611661 has 4 divisors (see below), whose sum is σ = 3912500641824. Its totient is φ = 3912488581500.

The previous prime is 3912494611639. The next prime is 3912494611667. The reversal of 3912494611661 is 1661164942193.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3912494611661 - 214 = 3912494595277 is a prime.

It is a super-2 number, since 2×39124946116612 (a number of 26 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3912494611667) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1905815 + ... + 3384836.

It is an arithmetic number, because the mean of its divisors is an integer number (978125160456).

Almost surely, 23912494611661 is an apocalyptic number.

It is an amenable number.

3912494611661 is a deficient number, since it is larger than the sum of its proper divisors (6030163).

3912494611661 is an equidigital number, since it uses as much as digits as its factorization.

3912494611661 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6030162.

The product of its digits is 1679616, while the sum is 53.

The spelling of 3912494611661 in words is "three trillion, nine hundred twelve billion, four hundred ninety-four million, six hundred eleven thousand, six hundred sixty-one".

Divisors: 1 739511 5290651 3912494611661