Base | Representation |
---|---|
bin | 1110100101000101… |
… | …0111000010001001 |
3 | 101002202012121201012 |
4 | 3221101113002021 |
5 | 31003343021441 |
6 | 1444202533305 |
7 | 165661260224 |
oct | 35121270211 |
9 | 11082177635 |
10 | 3913642121 |
11 | 1729170284 |
12 | 912807235 |
13 | 4a4a7648c |
14 | 291ab45bb |
15 | 17d8b79eb |
hex | e9457089 |
3913642121 has 2 divisors, whose sum is σ = 3913642122. Its totient is φ = 3913642120.
The previous prime is 3913642111. The next prime is 3913642127. The reversal of 3913642121 is 1212463193.
3913642121 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 3876432121 + 37210000 = 62261^2 + 6100^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-3913642121 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (3913642127) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1956821060 + 1956821061.
It is an arithmetic number, because the mean of its divisors is an integer number (1956821061).
Almost surely, 23913642121 is an apocalyptic number.
It is an amenable number.
3913642121 is a deficient number, since it is larger than the sum of its proper divisors (1).
3913642121 is an equidigital number, since it uses as much as digits as its factorization.
3913642121 is an evil number, because the sum of its binary digits is even.
The product of its digits is 7776, while the sum is 32.
The square root of 3913642121 is about 62559.1090169929. The cubic root of 3913642121 is about 1575.8941251818.
The spelling of 3913642121 in words is "three billion, nine hundred thirteen million, six hundred forty-two thousand, one hundred twenty-one".
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