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391379450041 is a prime number
BaseRepresentation
bin1011011001000000000…
…10000111100010111001
31101102012220111001120201
411230200002013202321
522403021114400131
6455444111522201
740163514302206
oct5544002074271
91342186431521
10391379450041
11140a8a550648
1263a28229361
132aba3685ac8
1414d2b322cad
15a2a9bc1761
hex5b200878b9

391379450041 has 2 divisors, whose sum is σ = 391379450042. Its totient is φ = 391379450040.

The previous prime is 391379450039. The next prime is 391379450089. The reversal of 391379450041 is 140054973193.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 216438022441 + 174941427600 = 465229^2 + 418260^2 .

It is an emirp because it is prime and its reverse (140054973193) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 391379450041 - 21 = 391379450039 is a prime.

It is a super-2 number, since 2×3913794500412 (a number of 24 digits) contains 22 as substring.

Together with 391379450039, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 391379449973 and 391379450000.

It is not a weakly prime, because it can be changed into another prime (391379450641) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 195689725020 + 195689725021.

It is an arithmetic number, because the mean of its divisors is an integer number (195689725021).

Almost surely, 2391379450041 is an apocalyptic number.

It is an amenable number.

391379450041 is a deficient number, since it is larger than the sum of its proper divisors (1).

391379450041 is an equidigital number, since it uses as much as digits as its factorization.

391379450041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 408240, while the sum is 46.

The spelling of 391379450041 in words is "three hundred ninety-one billion, three hundred seventy-nine million, four hundred fifty thousand, forty-one".