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3913839491 is a prime number
BaseRepresentation
bin1110100101001000…
…0111001110000011
3101002202120122110012
43221102013032003
531003420330431
61444211055135
7165663041522
oct35122071603
911082518405
103913839491
1117292955a1
129128a14ab
134a4b15273
14291b264b9
1517d90622b
hexe9487383

3913839491 has 2 divisors, whose sum is σ = 3913839492. Its totient is φ = 3913839490.

The previous prime is 3913839463. The next prime is 3913839493. The reversal of 3913839491 is 1949383193.

3913839491 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3913839491 is a prime.

It is a super-2 number, since 2×39138394912 = 30636279122622278162, which contains 22 as substring.

Together with 3913839493, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (3913839493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1956919745 + 1956919746.

It is an arithmetic number, because the mean of its divisors is an integer number (1956919746).

Almost surely, 23913839491 is an apocalyptic number.

3913839491 is a deficient number, since it is larger than the sum of its proper divisors (1).

3913839491 is an equidigital number, since it uses as much as digits as its factorization.

3913839491 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 629856, while the sum is 50.

The square root of 3913839491 is about 62560.6864652235. The cubic root of 3913839491 is about 1575.9206161916.

The spelling of 3913839491 in words is "three billion, nine hundred thirteen million, eight hundred thirty-nine thousand, four hundred ninety-one".