Base | Representation |
---|---|
bin | 111000111101111000001… |
… | …001111000110010000001 |
3 | 111212020121100010222011001 |
4 | 320331320021320302001 |
5 | 1003114332123030244 |
6 | 12154222544452001 |
7 | 552554454005302 |
oct | 70757011706201 |
9 | 14766540128131 |
10 | 3914731064449 |
11 | 127a2566a12a7 |
12 | 53284b61a001 |
13 | 2252081c289a |
14 | d768c8d87a9 |
15 | 6bc701605d4 |
hex | 38f78278c81 |
3914731064449 has 2 divisors, whose sum is σ = 3914731064450. Its totient is φ = 3914731064448.
The previous prime is 3914731064441. The next prime is 3914731064509. The reversal of 3914731064449 is 9444601374193.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3472781331600 + 441949732849 = 1863540^2 + 664793^2 .
It is a cyclic number.
It is not a de Polignac number, because 3914731064449 - 23 = 3914731064441 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3914731064449.
It is not a weakly prime, because it can be changed into another prime (3914731064441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1957365532224 + 1957365532225.
It is an arithmetic number, because the mean of its divisors is an integer number (1957365532225).
Almost surely, 23914731064449 is an apocalyptic number.
It is an amenable number.
3914731064449 is a deficient number, since it is larger than the sum of its proper divisors (1).
3914731064449 is an equidigital number, since it uses as much as digits as its factorization.
3914731064449 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7838208, while the sum is 55.
The spelling of 3914731064449 in words is "three trillion, nine hundred fourteen billion, seven hundred thirty-one million, sixty-four thousand, four hundred forty-nine".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •