Base | Representation |
---|---|
bin | 111000111101111000001… |
… | …100001010000010001001 |
3 | 111212020121101021012021022 |
4 | 320331320030022002021 |
5 | 1003114332301100101 |
6 | 12154223005322225 |
7 | 552554462033663 |
oct | 70757014120211 |
9 | 14766541235238 |
10 | 3914731659401 |
11 | 127a256a682a2 |
12 | 53284b866375 |
13 | 225208370624 |
14 | d768ca11533 |
15 | 6bc7022ba1b |
hex | 38f7830a089 |
3914731659401 has 2 divisors, whose sum is σ = 3914731659402. Its totient is φ = 3914731659400.
The previous prime is 3914731659389. The next prime is 3914731659439. The reversal of 3914731659401 is 1049561374193.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3221034236176 + 693697423225 = 1794724^2 + 832885^2 .
It is a cyclic number.
It is not a de Polignac number, because 3914731659401 - 210 = 3914731658377 is a prime.
It is not a weakly prime, because it can be changed into another prime (3914731659001) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1957365829700 + 1957365829701.
It is an arithmetic number, because the mean of its divisors is an integer number (1957365829701).
Almost surely, 23914731659401 is an apocalyptic number.
It is an amenable number.
3914731659401 is a deficient number, since it is larger than the sum of its proper divisors (1).
3914731659401 is an equidigital number, since it uses as much as digits as its factorization.
3914731659401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2449440, while the sum is 53.
The spelling of 3914731659401 in words is "three trillion, nine hundred fourteen billion, seven hundred thirty-one million, six hundred fifty-nine thousand, four hundred one".
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