Base | Representation |
---|---|
bin | 1011011010101110010… |
… | …10010011000001101101 |
3 | 1101111121100211101121011 |
4 | 11231113022103001231 |
5 | 22411414402403401 |
6 | 500115551305221 |
7 | 40225444610461 |
oct | 5552712230155 |
9 | 1344540741534 |
10 | 392304341101 |
11 | 141414633a22 |
12 | 64045b1b211 |
13 | 2acc0185c1a |
14 | 14db80bc4a1 |
15 | a310eb8451 |
hex | 5b5729306d |
392304341101 has 2 divisors, whose sum is σ = 392304341102. Its totient is φ = 392304341100.
The previous prime is 392304341089. The next prime is 392304341111. The reversal of 392304341101 is 101143403293.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 330049101001 + 62255240100 = 574499^2 + 249510^2 .
It is an emirp because it is prime and its reverse (101143403293) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 392304341101 - 219 = 392303816813 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (392304341111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 196152170550 + 196152170551.
It is an arithmetic number, because the mean of its divisors is an integer number (196152170551).
Almost surely, 2392304341101 is an apocalyptic number.
It is an amenable number.
392304341101 is a deficient number, since it is larger than the sum of its proper divisors (1).
392304341101 is an equidigital number, since it uses as much as digits as its factorization.
392304341101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776, while the sum is 31.
Adding to 392304341101 its reverse (101143403293), we get a palindrome (493447744394).
The spelling of 392304341101 in words is "three hundred ninety-two billion, three hundred four million, three hundred forty-one thousand, one hundred one".
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