Base | Representation |
---|---|
bin | 101100101110000110111010… |
… | …1001010100011101000011100 |
3 | 1220120210100011122001101010122 |
4 | 1121130031311022203220130 |
5 | 403024343244133043122 |
6 | 3512341240513054112 |
7 | 145566456521456612 |
oct | 13134156512435034 |
9 | 1816710148041118 |
10 | 393365135440412 |
11 | 10437a242a48043 |
12 | 3815096bb57338 |
13 | 13b6523340b955 |
14 | 6d1cd8d0836b2 |
15 | 30724e35ed142 |
hex | 165c3752a3a1c |
393365135440412 has 6 divisors (see below), whose sum is σ = 688388987020728. Its totient is φ = 196682567720204.
The previous prime is 393365135440411. The next prime is 393365135440421. The reversal of 393365135440412 is 214044531563393.
It is a super-2 number, since 2×3933651354404122 (a number of 30 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (393365135440411) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 49170641930048 + ... + 49170641930055.
It is an arithmetic number, because the mean of its divisors is an integer number (114731497836788).
Almost surely, 2393365135440412 is an apocalyptic number.
It is an amenable number.
393365135440412 is a deficient number, since it is larger than the sum of its proper divisors (295023851580316).
393365135440412 is a wasteful number, since it uses less digits than its factorization.
393365135440412 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 98341283860107 (or 98341283860105 counting only the distinct ones).
The product of its (nonzero) digits is 13996800, while the sum is 53.
The spelling of 393365135440412 in words is "three hundred ninety-three trillion, three hundred sixty-five billion, one hundred thirty-five million, four hundred forty thousand, four hundred twelve".
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