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393500113 is a prime number
BaseRepresentation
bin10111011101000…
…101010111010001
31000102102212200021
4113131011113101
51301214000423
6103014023441
712515460436
oct2735052721
91012385607
10393500113
11192136506
12ab947b81
13636a6c06
143a391b8d
152482c95d
hex177455d1

393500113 has 2 divisors, whose sum is σ = 393500114. Its totient is φ = 393500112.

The previous prime is 393500099. The next prime is 393500117. The reversal of 393500113 is 311005393.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 347897104 + 45603009 = 18652^2 + 6753^2 .

It is an emirp because it is prime and its reverse (311005393) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-393500113 is a prime.

It is not a weakly prime, because it can be changed into another prime (393500117) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 196750056 + 196750057.

It is an arithmetic number, because the mean of its divisors is an integer number (196750057).

Almost surely, 2393500113 is an apocalyptic number.

It is an amenable number.

393500113 is a deficient number, since it is larger than the sum of its proper divisors (1).

393500113 is an equidigital number, since it uses as much as digits as its factorization.

393500113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1215, while the sum is 25.

The square root of 393500113 is about 19836.8372731139. The cubic root of 393500113 is about 732.7935203444.

The spelling of 393500113 in words is "three hundred ninety-three million, five hundred thousand, one hundred thirteen".