Base | Representation |
---|---|
bin | 111001010010010000011… |
… | …011010101011110100100 |
3 | 111221100002100002222100221 |
4 | 321102100123111132210 |
5 | 1003444140430044400 |
6 | 12212242145214124 |
7 | 554260641326242 |
oct | 71222033253644 |
9 | 14840070088327 |
10 | 3936613128100 |
11 | 1288565535624 |
12 | 536b37931344 |
13 | 2272b4791043 |
14 | d8766b39792 |
15 | 6c601244c1a |
hex | 394906d57a4 |
3936613128100 has 27 divisors (see below), whose sum is σ = 8542493542947. Its totient is φ = 1574637314880.
The previous prime is 3936613128083. The next prime is 3936613128113. The reversal of 3936613128100 is 18213166393.
The square root of 3936613128100 is 1984090.
It is a perfect power (a square), and thus also a powerful number.
It can be written as a sum of positive squares in 4 ways, for example, as 976313943396 + 2960299184704 = 988086^2 + 1720552^2 .
It is a super-2 number, since 2×39366131281002 (a number of 26 digits) contains 22 as substring.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 8 ways as a sum of consecutive naturals, for example, 19741696 + ... + 19940104.
Almost surely, 23936613128100 is an apocalyptic number.
3936613128100 is the 1984090-th square number.
It is an amenable number.
3936613128100 is an abundant number, since it is smaller than the sum of its proper divisors (4605880414847).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
3936613128100 is an frugal number, since it uses more digits than its factorization.
3936613128100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 396832 (or 198416 counting only the distinct ones).
The product of its (nonzero) digits is 139968, while the sum is 43.
The spelling of 3936613128100 in words is "three trillion, nine hundred thirty-six billion, six hundred thirteen million, one hundred twenty-eight thousand, one hundred".
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