3938134118400 has 624 divisors, whose sum is σ = 14564583541120. Its totient is φ = 1043103744000.

The previous prime is 3938134118327. The next prime is 3938134118407. The reversal of 3938134118400 is 48114318393.

3938134118400 is a `hidden beast` number, since 393 + 81 + 3 + 4 + 1 + 184 + 0 + 0 = 666.

It is a super-2 number, since 2×3938134118400² (a number of 26 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (45).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (3938134118407) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 417480084 + ... + 417489516.

Almost surely, 2^{3938134118400} is an apocalyptic number.

3938134118400 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 3938134118400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (7282291770560).

3938134118400 is an abundant number, since it is smaller than the sum of its proper divisors (10626449422720).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3938134118400 is a wasteful number, since it uses less digits than its factorization.

3938134118400 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 9627 (or 9594 counting only the distinct ones).

The product of its (nonzero) digits is 248832, while the sum is 45.

The spelling of 3938134118400 in words is "three trillion, nine hundred thirty-eight billion, one hundred thirty-four million, one hundred eighteen thousand, four hundred".