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3938444841413 is a prime number
BaseRepresentation
bin111001010011111101100…
…110110001000111000101
3111221111210222210122122202
4321103331212301013011
51004011413334411123
612213144021204245
7554354222536265
oct71237546610705
914844728718582
103938444841413
11128931548a985
12537369260685
13227517105b84
14d889c1097a5
156c6abe64a28
hex394fd9b11c5

3938444841413 has 2 divisors, whose sum is σ = 3938444841414. Its totient is φ = 3938444841412.

The previous prime is 3938444841407. The next prime is 3938444841449. The reversal of 3938444841413 is 3141484448393.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3728733966049 + 209710875364 = 1930993^2 + 457942^2 .

It is a cyclic number.

It is not a de Polignac number, because 3938444841413 - 210 = 3938444840389 is a prime.

It is a super-2 number, since 2×39384448414132 (a number of 26 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3938444844413) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1969222420706 + 1969222420707.

It is an arithmetic number, because the mean of its divisors is an integer number (1969222420707).

Almost surely, 23938444841413 is an apocalyptic number.

It is an amenable number.

3938444841413 is a deficient number, since it is larger than the sum of its proper divisors (1).

3938444841413 is an equidigital number, since it uses as much as digits as its factorization.

3938444841413 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 15925248, while the sum is 56.

The spelling of 3938444841413 in words is "three trillion, nine hundred thirty-eight billion, four hundred forty-four million, eight hundred forty-one thousand, four hundred thirteen".