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394011843317 is a prime number
BaseRepresentation
bin1011011101111001110…
…11111001101011110101
31101200000100210111021222
411232330323321223311
522423414012441232
6501001225120125
740315660260161
oct5567473715365
91350010714258
10394011843317
11142110460684
1264441929045
132b202b5b171
14150dab97ca1
15a3b0d4ed12
hex5bbcef9af5

394011843317 has 2 divisors, whose sum is σ = 394011843318. Its totient is φ = 394011843316.

The previous prime is 394011843217. The next prime is 394011843331. The reversal of 394011843317 is 713348110493.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 222445232881 + 171566610436 = 471641^2 + 414206^2 .

It is an emirp because it is prime and its reverse (713348110493) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 394011843317 - 214 = 394011826933 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (394011843377) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 197005921658 + 197005921659.

It is an arithmetic number, because the mean of its divisors is an integer number (197005921659).

Almost surely, 2394011843317 is an apocalyptic number.

It is an amenable number.

394011843317 is a deficient number, since it is larger than the sum of its proper divisors (1).

394011843317 is an equidigital number, since it uses as much as digits as its factorization.

394011843317 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 217728, while the sum is 44.

The spelling of 394011843317 in words is "three hundred ninety-four billion, eleven million, eight hundred forty-three thousand, three hundred seventeen".