3941254133 has 2 divisors, whose sum is σ = 3941254134. Its totient is φ = 3941254132.

The previous prime is 3941254073. The next prime is 3941254169. The reversal of 3941254133 is 3314521493.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2849744689 + 1091509444 = 53383^2 + 33038^2 .

It is a cyclic number.

It is not a de Polignac number, because 3941254133 - 2⁶ = 3941254069 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3941254093 and 3941254102.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3941251133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1970627066 + 1970627067.

It is an arithmetic number, because the mean of its divisors is an integer number (1970627067).

Almost surely, 2^3941254133 is an apocalyptic number.

It is an amenable number.

3941254133 is a deficient number, since it is larger than the sum of its proper divisors (1).

3941254133 is an equidigital number, since it uses as much as digits as its factorization.

3941254133 is an evil number, because the sum of its binary digits is even.

The product of its digits is 38880, while the sum is 35.

The square root of 3941254133 is about 62779.4085110715. The cubic root of 3941254133 is about 1579.5915908836.

The spelling of 3941254133 in words is "three billion, nine hundred forty-one million, two hundred fifty-four thousand, one hundred thirty-three".