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3942170712517 is a prime number
BaseRepresentation
bin111001010111011011101…
…011110101100111000101
3111221212102122200111221211
4321113123223311213011
51004042031200300032
612215001435411421
7554545444114252
oct71273353654705
914855378614854
103942170712517
11128a95765aaa4
12538028bb3b71
1322798bcb732b
14d8b32ca2429
156c8290db747
hex395dbaf59c5

3942170712517 has 2 divisors, whose sum is σ = 3942170712518. Its totient is φ = 3942170712516.

The previous prime is 3942170712479. The next prime is 3942170712533. The reversal of 3942170712517 is 7152170712493.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3674432768161 + 267737944356 = 1916881^2 + 517434^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3942170712517 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3942170712317) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1971085356258 + 1971085356259.

It is an arithmetic number, because the mean of its divisors is an integer number (1971085356259).

Almost surely, 23942170712517 is an apocalyptic number.

It is an amenable number.

3942170712517 is a deficient number, since it is larger than the sum of its proper divisors (1).

3942170712517 is an equidigital number, since it uses as much as digits as its factorization.

3942170712517 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 740880, while the sum is 49.

The spelling of 3942170712517 in words is "three trillion, nine hundred forty-two billion, one hundred seventy million, seven hundred twelve thousand, five hundred seventeen".