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3943015834013 is a prime number
BaseRepresentation
bin111001011000001110000…
…011101110000110011101
3111221221121112221010200222
4321120032003232012131
51004100244023142023
612215221345331125
7554605415406314
oct71301603560635
914857545833628
103943015834013
11129025070a313
12538224036aa5
13227a95107c19
14d8bb321527b
156c8783c7cc8
hex3960e0ee19d

3943015834013 has 2 divisors, whose sum is σ = 3943015834014. Its totient is φ = 3943015834012.

The previous prime is 3943015833949. The next prime is 3943015834103. The reversal of 3943015834013 is 3104385103493.

3943015834013 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

Together with next prime (3943015834103) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 3035306137369 + 907709696644 = 1742213^2 + 952738^2 .

It is a cyclic number.

It is not a de Polignac number, because 3943015834013 - 26 = 3943015833949 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3943015834213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1971507917006 + 1971507917007.

It is an arithmetic number, because the mean of its divisors is an integer number (1971507917007).

Almost surely, 23943015834013 is an apocalyptic number.

It is an amenable number.

3943015834013 is a deficient number, since it is larger than the sum of its proper divisors (1).

3943015834013 is an equidigital number, since it uses as much as digits as its factorization.

3943015834013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 466560, while the sum is 44.

The spelling of 3943015834013 in words is "three trillion, nine hundred forty-three billion, fifteen million, eight hundred thirty-four thousand, thirteen".