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39431740013 is a prime number
BaseRepresentation
bin100100101110010100…
…001001101001101101
310202210001202221100022
4210232110021221231
51121224011140023
630040435011525
72564104155101
oct445624115155
9122701687308
1039431740013
11157a5209996
127785739ba5
13394541a953
141ca0d27901
15105bb887c8
hex92e509a6d

39431740013 has 2 divisors, whose sum is σ = 39431740014. Its totient is φ = 39431740012.

The previous prime is 39431739983. The next prime is 39431740031. The reversal of 39431740013 is 31004713493.

Together with next prime (39431740031) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 23475755524 + 15955984489 = 153218^2 + 126317^2 .

It is a cyclic number.

It is not a de Polignac number, because 39431740013 - 222 = 39427545709 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (39431740093) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 19715870006 + 19715870007.

It is an arithmetic number, because the mean of its divisors is an integer number (19715870007).

Almost surely, 239431740013 is an apocalyptic number.

It is an amenable number.

39431740013 is a deficient number, since it is larger than the sum of its proper divisors (1).

39431740013 is an equidigital number, since it uses as much as digits as its factorization.

39431740013 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27216, while the sum is 35.

The spelling of 39431740013 in words is "thirty-nine billion, four hundred thirty-one million, seven hundred forty thousand, thirteen".