Base | Representation |
---|---|
bin | 101100110101010111010010… |
… | …0100111011011010000110011 |
3 | 1220201022200012012102111200111 |
4 | 1121222232210213123100303 |
5 | 403142213110132401011 |
6 | 3514423322521002151 |
7 | 146031512004111223 |
oct | 13152564447332063 |
9 | 1821280165374614 |
10 | 394362363950131 |
11 | 1047241594982a5 |
12 | 38292099923357 |
13 | 13c0829944cac5 |
14 | 6d553513a8083 |
15 | 308d40b8ac121 |
hex | 166aba49db433 |
394362363950131 has 2 divisors, whose sum is σ = 394362363950132. Its totient is φ = 394362363950130.
The previous prime is 394362363950069. The next prime is 394362363950143. The reversal of 394362363950131 is 131059363263493.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 394362363950131 - 237 = 394224924996659 is a prime.
It is a super-2 number, since 2×3943623639501312 (a number of 30 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (394362363950431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 197181181975065 + 197181181975066.
It is an arithmetic number, because the mean of its divisors is an integer number (197181181975066).
Almost surely, 2394362363950131 is an apocalyptic number.
394362363950131 is a deficient number, since it is larger than the sum of its proper divisors (1).
394362363950131 is an equidigital number, since it uses as much as digits as its factorization.
394362363950131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28343520, while the sum is 58.
The spelling of 394362363950131 in words is "three hundred ninety-four trillion, three hundred sixty-two billion, three hundred sixty-three million, nine hundred fifty thousand, one hundred thirty-one".
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