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3947389195357 is a prime number
BaseRepresentation
bin111001011100010010101…
…110110001010001011101
3111222100220100011220122001
4321130102232301101131
51004133223113222412
612221223333522301
7555121661356036
oct71342256612135
914870810156561
103947389195357
111292095324433
125390447a3391
132283111a1bba
14d90a9d97a8d
156ca322ed957
hex39712bb145d

3947389195357 has 2 divisors, whose sum is σ = 3947389195358. Its totient is φ = 3947389195356.

The previous prime is 3947389195303. The next prime is 3947389195369. The reversal of 3947389195357 is 7535919837493.

3947389195357 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2349518758596 + 1597870436761 = 1532814^2 + 1264069^2 .

It is a cyclic number.

It is not a de Polignac number, because 3947389195357 - 211 = 3947389193309 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 3947389195357.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3947389195457) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1973694597678 + 1973694597679.

It is an arithmetic number, because the mean of its divisors is an integer number (1973694597679).

Almost surely, 23947389195357 is an apocalyptic number.

It is an amenable number.

3947389195357 is a deficient number, since it is larger than the sum of its proper divisors (1).

3947389195357 is an equidigital number, since it uses as much as digits as its factorization.

3947389195357 is an evil number, because the sum of its binary digits is even.

The product of its digits is 771573600, while the sum is 73.

The spelling of 3947389195357 in words is "three trillion, nine hundred forty-seven billion, three hundred eighty-nine million, one hundred ninety-five thousand, three hundred fifty-seven".