Base | Representation |
---|---|
bin | 1110101101110010… |
… | …0100010000011111 |
3 | 101012021212121120111 |
4 | 3223130210100133 |
5 | 31042213244203 |
6 | 1451545030451 |
7 | 166613405353 |
oct | 35334442037 |
9 | 11167777514 |
10 | 3950134303 |
11 | 1747825405 |
12 | 922a85427 |
13 | 4ac4b249b |
14 | 296893463 |
15 | 181bc526d |
hex | eb72441f |
3950134303 has 2 divisors, whose sum is σ = 3950134304. Its totient is φ = 3950134302.
The previous prime is 3950134273. The next prime is 3950134313. The reversal of 3950134303 is 3034310593.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3950134303 - 225 = 3916579871 is a prime.
It is a super-3 number, since 3×39501343033 (a number of 30 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (3950134313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1975067151 + 1975067152.
It is an arithmetic number, because the mean of its divisors is an integer number (1975067152).
Almost surely, 23950134303 is an apocalyptic number.
3950134303 is a deficient number, since it is larger than the sum of its proper divisors (1).
3950134303 is an equidigital number, since it uses as much as digits as its factorization.
3950134303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14580, while the sum is 31.
The square root of 3950134303 is about 62850.0938981001. The cubic root of 3950134303 is about 1580.7770443477. Note that the first 3 decimals are identical.
Adding to 3950134303 its reverse (3034310593), we get a palindrome (6984444896).
The spelling of 3950134303 in words is "three billion, nine hundred fifty million, one hundred thirty-four thousand, three hundred three".
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