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3950134303 is a prime number
BaseRepresentation
bin1110101101110010…
…0100010000011111
3101012021212121120111
43223130210100133
531042213244203
61451545030451
7166613405353
oct35334442037
911167777514
103950134303
111747825405
12922a85427
134ac4b249b
14296893463
15181bc526d
hexeb72441f

3950134303 has 2 divisors, whose sum is σ = 3950134304. Its totient is φ = 3950134302.

The previous prime is 3950134273. The next prime is 3950134313. The reversal of 3950134303 is 3034310593.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 3950134303 - 225 = 3916579871 is a prime.

It is a super-3 number, since 3×39501343033 (a number of 30 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3950134313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1975067151 + 1975067152.

It is an arithmetic number, because the mean of its divisors is an integer number (1975067152).

Almost surely, 23950134303 is an apocalyptic number.

3950134303 is a deficient number, since it is larger than the sum of its proper divisors (1).

3950134303 is an equidigital number, since it uses as much as digits as its factorization.

3950134303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14580, while the sum is 31.

The square root of 3950134303 is about 62850.0938981001. The cubic root of 3950134303 is about 1580.7770443477. Note that the first 3 decimals are identical.

Adding to 3950134303 its reverse (3034310593), we get a palindrome (6984444896).

The spelling of 3950134303 in words is "three billion, nine hundred fifty million, one hundred thirty-four thousand, three hundred three".