Base | Representation |
---|---|
bin | 111001110001011000100… |
… | …000011100110010101111 |
3 | 112001112100112122212202122 |
4 | 321301120200130302233 |
5 | 1010021112334324210 |
6 | 12235450405143155 |
7 | 556553106006050 |
oct | 71613040346257 |
9 | 15045315585678 |
10 | 3970034683055 |
11 | 12a0756097521 |
12 | 5415046baabb |
13 | 22a4ac98806c |
14 | da217762727 |
15 | 6d40a432b55 |
hex | 39c5881ccaf |
3970034683055 has 64 divisors (see below), whose sum is σ = 5773769579520. Its totient is φ = 2559898598400.
The previous prime is 3970034683003. The next prime is 3970034683103. The reversal of 3970034683055 is 5503864300793.
3970034683055 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 3970034683055 - 216 = 3970034617519 is a prime.
It is a super-2 number, since 2×39700346830552 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3970034682988 and 3970034683006.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 101357675 + ... + 101396835.
It is an arithmetic number, because the mean of its divisors is an integer number (90215149680).
Almost surely, 23970034683055 is an apocalyptic number.
3970034683055 is a gapful number since it is divisible by the number (35) formed by its first and last digit.
3970034683055 is a deficient number, since it is larger than the sum of its proper divisors (1803734896465).
3970034683055 is a wasteful number, since it uses less digits than its factorization.
3970034683055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40320.
The product of its (nonzero) digits is 8164800, while the sum is 53.
The spelling of 3970034683055 in words is "three trillion, nine hundred seventy billion, thirty-four million, six hundred eighty-three thousand, fifty-five".
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