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3973947000000 = 263561324649
BaseRepresentation
bin111001110101000001101…
…100110000010011000000
3112001220110012101011200020
4321311001230300103000
51010102120413000000
612241334523453440
7560052053106645
oct71650154602300
915056405334606
103973947000000
1112a238353210a
12542216987280
1322a9843892c3
14da4a91addcc
156d588b37ba0
hex39d41b304c0

3973947000000 has 196 divisors, whose sum is σ = 13142843488200. Its totient is φ = 1059718400000.

The previous prime is 3973946999987. The next prime is 3973947000007. The reversal of 3973947000000 is 7493793.

It is not an unprimeable number, because it can be changed into a prime (3973947000007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 2337676 + ... + 3662324.

Almost surely, 23973947000000 is an apocalyptic number.

3973947000000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 3973947000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (6571421744100).

3973947000000 is an abundant number, since it is smaller than the sum of its proper divisors (9168896488200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

3973947000000 is an frugal number, since it uses more digits than its factorization.

3973947000000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1324694 (or 1324659 counting only the distinct ones).

The product of its (nonzero) digits is 142884, while the sum is 42.

The spelling of 3973947000000 in words is "three trillion, nine hundred seventy-three billion, nine hundred forty-seven million", and thus it is an aban number.